Optimal. Leaf size=281 \[ -\frac{\sqrt{2} \left (-3 a^2 C+5 a b B-2 b^2 C\right ) \sin (c+d x) \sqrt [3]{\frac{a+b \cos (c+d x)}{a+b}} F_1\left (\frac{1}{2};\frac{1}{2},\frac{1}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right )}{5 b^2 d \sqrt{\cos (c+d x)+1} \sqrt [3]{a+b \cos (c+d x)}}+\frac{\sqrt{2} (5 b B-3 a C) \sin (c+d x) (a+b \cos (c+d x))^{2/3} F_1\left (\frac{1}{2};\frac{1}{2},-\frac{2}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right )}{5 b^2 d \sqrt{\cos (c+d x)+1} \left (\frac{a+b \cos (c+d x)}{a+b}\right )^{2/3}}+\frac{3 C \sin (c+d x) (a+b \cos (c+d x))^{2/3}}{5 b d} \]
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Rubi [A] time = 0.323062, antiderivative size = 281, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 34, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.147, Rules used = {3023, 2756, 2665, 139, 138} \[ -\frac{\sqrt{2} \left (-3 a^2 C+5 a b B-2 b^2 C\right ) \sin (c+d x) \sqrt [3]{\frac{a+b \cos (c+d x)}{a+b}} F_1\left (\frac{1}{2};\frac{1}{2},\frac{1}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right )}{5 b^2 d \sqrt{\cos (c+d x)+1} \sqrt [3]{a+b \cos (c+d x)}}+\frac{\sqrt{2} (5 b B-3 a C) \sin (c+d x) (a+b \cos (c+d x))^{2/3} F_1\left (\frac{1}{2};\frac{1}{2},-\frac{2}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right )}{5 b^2 d \sqrt{\cos (c+d x)+1} \left (\frac{a+b \cos (c+d x)}{a+b}\right )^{2/3}}+\frac{3 C \sin (c+d x) (a+b \cos (c+d x))^{2/3}}{5 b d} \]
Antiderivative was successfully verified.
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Rule 3023
Rule 2756
Rule 2665
Rule 139
Rule 138
Rubi steps
\begin{align*} \int \frac{B \cos (c+d x)+C \cos ^2(c+d x)}{\sqrt [3]{a+b \cos (c+d x)}} \, dx &=\frac{3 C (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b d}+\frac{3 \int \frac{\frac{2 b C}{3}+\frac{1}{3} (5 b B-3 a C) \cos (c+d x)}{\sqrt [3]{a+b \cos (c+d x)}} \, dx}{5 b}\\ &=\frac{3 C (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b d}+\frac{(5 b B-3 a C) \int (a+b \cos (c+d x))^{2/3} \, dx}{5 b^2}-\frac{\left (5 a b B-3 a^2 C-2 b^2 C\right ) \int \frac{1}{\sqrt [3]{a+b \cos (c+d x)}} \, dx}{5 b^2}\\ &=\frac{3 C (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b d}-\frac{((5 b B-3 a C) \sin (c+d x)) \operatorname{Subst}\left (\int \frac{(a+b x)^{2/3}}{\sqrt{1-x} \sqrt{1+x}} \, dx,x,\cos (c+d x)\right )}{5 b^2 d \sqrt{1-\cos (c+d x)} \sqrt{1+\cos (c+d x)}}+\frac{\left (\left (5 a b B-3 a^2 C-2 b^2 C\right ) \sin (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} \sqrt{1+x} \sqrt [3]{a+b x}} \, dx,x,\cos (c+d x)\right )}{5 b^2 d \sqrt{1-\cos (c+d x)} \sqrt{1+\cos (c+d x)}}\\ &=\frac{3 C (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b d}-\frac{\left ((5 b B-3 a C) (a+b \cos (c+d x))^{2/3} \sin (c+d x)\right ) \operatorname{Subst}\left (\int \frac{\left (-\frac{a}{-a-b}-\frac{b x}{-a-b}\right )^{2/3}}{\sqrt{1-x} \sqrt{1+x}} \, dx,x,\cos (c+d x)\right )}{5 b^2 d \sqrt{1-\cos (c+d x)} \sqrt{1+\cos (c+d x)} \left (-\frac{a+b \cos (c+d x)}{-a-b}\right )^{2/3}}+\frac{\left (\left (5 a b B-3 a^2 C-2 b^2 C\right ) \sqrt [3]{-\frac{a+b \cos (c+d x)}{-a-b}} \sin (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} \sqrt{1+x} \sqrt [3]{-\frac{a}{-a-b}-\frac{b x}{-a-b}}} \, dx,x,\cos (c+d x)\right )}{5 b^2 d \sqrt{1-\cos (c+d x)} \sqrt{1+\cos (c+d x)} \sqrt [3]{a+b \cos (c+d x)}}\\ &=\frac{3 C (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b d}+\frac{\sqrt{2} (5 b B-3 a C) F_1\left (\frac{1}{2};\frac{1}{2},-\frac{2}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right ) (a+b \cos (c+d x))^{2/3} \sin (c+d x)}{5 b^2 d \sqrt{1+\cos (c+d x)} \left (\frac{a+b \cos (c+d x)}{a+b}\right )^{2/3}}-\frac{\sqrt{2} \left (5 a b B-3 a^2 C-2 b^2 C\right ) F_1\left (\frac{1}{2};\frac{1}{2},\frac{1}{3};\frac{3}{2};\frac{1}{2} (1-\cos (c+d x)),\frac{b (1-\cos (c+d x))}{a+b}\right ) \sqrt [3]{\frac{a+b \cos (c+d x)}{a+b}} \sin (c+d x)}{5 b^2 d \sqrt{1+\cos (c+d x)} \sqrt [3]{a+b \cos (c+d x)}}\\ \end{align*}
Mathematica [A] time = 2.0313, size = 263, normalized size = 0.94 \[ -\frac{3 \csc (c+d x) (a+b \cos (c+d x))^{2/3} \left (5 \left (3 a^2 C-5 a b B+2 b^2 C\right ) \sqrt{-\frac{b (\cos (c+d x)-1)}{a+b}} \sqrt{-\frac{b (\cos (c+d x)+1)}{a-b}} F_1\left (\frac{2}{3};\frac{1}{2},\frac{1}{2};\frac{5}{3};\frac{a+b \cos (c+d x)}{a-b},\frac{a+b \cos (c+d x)}{a+b}\right )+2 (5 b B-3 a C) \sqrt{-\frac{b (\cos (c+d x)-1)}{a+b}} \sqrt{\frac{b (\cos (c+d x)+1)}{b-a}} (a+b \cos (c+d x)) F_1\left (\frac{5}{3};\frac{1}{2},\frac{1}{2};\frac{8}{3};\frac{a+b \cos (c+d x)}{a-b},\frac{a+b \cos (c+d x)}{a+b}\right )-10 b^2 C \sin ^2(c+d x)\right )}{50 b^3 d} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.335, size = 0, normalized size = 0. \begin{align*} \int{(B\cos \left ( dx+c \right ) +C \left ( \cos \left ( dx+c \right ) \right ) ^{2}){\frac{1}{\sqrt [3]{a+b\cos \left ( dx+c \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right )}{{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{1}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right )}{{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{1}{3}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right )}{{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{1}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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